7x=x^2+18

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Solution for 7x=x^2+18 equation: 



7x=x^2+18

We move all terms to the left:

7x-(x^2+18)=0

We get rid of parentheses

-x^2+7x-18=0

We add all the numbers together, and all the variables

-1x^2+7x-18=0

a = -1; b = 7; c = -18;
Δ = b2-4ac
Δ = 72-4·(-1)·(-18)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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